• ARRAY OPERATION :WHICH INCLUDES SUM OF ARRAY ,AVERAGE OF ARRAY, TOTAL EVEN NUMBER ,TOTAL ODD NUMBER OF ARRAY ,NEW VALUE TO ENTER IN ARRAY AND DISPLAY 

*EXAMPLE*
many operation of array in c program


  • Following is a code of array operation in c:-

INPUT:




//code written by www.techsayright.blogspot.com//

#include<stdio.h>
#include<conio.h>

int a[10];
int sumc()
{
 int sum=0;
 int i;

 for(i=0;i<=9;i++)
 {
  sum=sum+a[i];
 }
 return sum;
}

void avg()
{
 int sum=sumc();
 printf("average value is %f",(float)sum/10);
}

void total_even()
{
 int count=0;
 int i;

 for(i=0;i<=9;i++)
 {
  if(a[i]%2==0)
  count++;
 }
 printf("total even number=%d",count);
}

void total_odd()
{
 int count=0;
 int i;

 for(i=0;i<=9;i++)
 {
  if(a[i]%2==1)
  count++;
 }
 printf("total odd number=%d",count);
}

void new_value()
{
 int i;

 for(i=0;i<=9;i++)
 {
  printf("enter new value a[%d]",i);
  scanf("%d",&a[i]);
 }
}

void display()
{
 int i;

 for(i=0;i<=9;i++)
 {
  printf("value at a[%d]=%d\n",i,a[i]);
 }
}

void main()
{
 int choice,i,sum;
 clrscr();

 for(i=0;i<=9;i++)
 {
  printf(" enter the value of =",i);
  scanf("%d",&a[i]);
 }
 do
 {
  printf("\n select from \n1-sum \n2-average \n3-total even \n4-total odd \n5-new value \n6-dispay \n7-exit \nenter your choice:");
  scanf("%d",&choice);

  switch(choice)
  {
   case 1:
    int sum=sumc();
    printf("sum of array=%d",sum);
    break;

   case 2:
    avg();
    break;

   case 3:
    total_even();
    break;

   case 4:
    total_odd();
    break;

   case 5:
    new_value();
    break;

   case 6:
    display();
    break;

   case 7:
    break;

   default:
    printf("enter a valid choice");
  }
 }while(choice!=7);
getch();
}
















OUTPUT:









*happy coding*☺











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